If U={2, 4, 6, 8, 12, 14, 17}, where U is the universal set and some set A={1, 4, 6, 11, 12}. The set A' is
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Solution
The complement of A is the set of elements of the universal set that are not elements of A. example. We will define our universal set as U = {1, 2, 3, 4, 5, 6, 7}, and we will define our subset as E = {1, 3, 4}. The complement of E is the set of all the elements in Uthat are not in E. Therefore, the complement of E is {2, 5, 6, 7}. here A' is the compement of A A'={2,8,14,17}