If $U = 4 r^{3}$ then find the corresponding force.

12 r^{2} (^r)

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12 r^{2} (^- r)

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r^{3} (^r)

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- r^{3} (^r)

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Solution

The correct option is C $12 r^{2} (^- r)$

$F = - \frac{d (U)}{d x}$

$= \frac{- d}{d x} (4 r^{3})$

$= 12 r^{2} (-^r)$

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Similar questions

12 \infty \sum r = 1 \frac{12 r^{2} + 1}{64 r^{6} - 48 r^{4} + 12 r^{2} - 1}

lim n \to \infty n \sum r = 1 {cot}^{- 1} (2 r^{2}) =

U (r)

F = K / r^{2}

\to E = k \frac{q}{r^{3}}^r

Φ = q_{e n c l o s e d} / ϵ_{0}

^i \times (^r \times^i) +^j \times (^r \times j) +^k \times (^r \times^k)

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