If u-logxn-yn-xe-ye- then - x- u- x-

The correct option is C n e e^u=x^n+y^nx^e+y^e e^u is a homogeneous eq^n of degree =n e We know that =e^u ( ∑ xdy/dx )=nz ;wher ...

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Standard XII

Mathematics

Equation of Circle with (h,k) as Center

If u=logxn+...

Question

If $u = log (\frac{x^{n} + y^{n}}{x^{e} + y^{e}})$ , then $\sum x \frac{\partial u}{\partial x} =$

n

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e

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n - e

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\frac{n}{e}

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Solution

The correct option is C $n - e$
$e^{u} = \frac{x^{n} + y^{n}}{x^{e} + y^{e}}$
$e^{u}$ is a homogeneous $e q^{n}$ of degree $= n - e$
We know that $= e^{u} (\sum x \frac{d y}{d x}) = n z$ ;where n is degree of equation.
$\sum x \frac{d y}{d x} = n - e$

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If u=log(xn+ynxe+ye), then ∑x∂u∂x=

The correct option is C n−eeu=xn+ynxe+yeeu is a homogeneous eqn of degree=n−eWe know that =eu(∑xdydx)=nz ;where n is degree of equation.∑xdydx=n−e

If $u = log (\frac{x^{n} + y^{n}}{x^{e} + y^{e}})$ , then $\sum x \frac{\partial u}{\partial x} =$

The correct option is C $n - e$
$e^{u} = \frac{x^{n} + y^{n}}{x^{e} + y^{e}}$
$e^{u}$ is a homogeneous $e q^{n}$ of degree $= n - e$
We know that $= e^{u} (\sum x \frac{d y}{d x}) = n z$ ;where n is degree of equation.
$\sum x \frac{d y}{d x} = n - e$