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Question


If u=tan1[(xyx+y)3/2] then Σxux=?

A
0
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B
sinu
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C
tanu
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D
1
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Solution

The correct option is A 0
tanu=(xyx+y)3/2
tanu homogeneous of degree=0
sec2u(xdydx)=ntanu (Rules formula)
xdydx=0

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