Let U be the universal set containing 700 elements. If A, B are sub-sets of U such that n (A) = 200, n(B) =300 and $n (A \cap B)$ = 100. Then , $n (A^{'} \cap B^{'}) =$

Q. If

A

and

B

are two sets and

U

is the universal set such that

n (U) = 700, n (A) = 200, n (B) = 300

and

n (A \cap B) = 100

, find

n (A^{'} \cap B^{'})

If there are two sets A and B such that $n (¯ A \cap ¯ B) = n (A \cap B)$ . Universal set contains 'x' elements. Then n (A) + n (B) is

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If U is the universal set with 100 element; A and B are two set such that n(A)=50, n(B)=60, n(A ∩ B)=20, then n(A′ ∩ B′)=

The correct option is C 10 n(A ∪ B)=n(A)+n(B)−n(A ∩ B) =50+60−20=90 Now, n(A′ ∩ B′)=n(A ∪ B)′ =n(U)−n(A ∪ B) =100−90=10

If $U$ is the universal set with 100 element; $A$ and $B$ are two set such that $n (A) = 50, n (B) = 60, n (A \cap B) = 20$ , then $n (A^{'} \cap B^{'}) =$

The correct option is C $10$
$n (A \cup B) = n (A) + n (B) - n (A \cap B)$
$= 50 + 60 - 20 = 90$
$Now, n (A^{'} \cap B^{'}) = n (A \cup B)^{'}$
$= n (U) - n (A \cup B)$
$= 100 - 90 = 10$