If u-logax3-y3-z3- then x- u- x-y- u- y-z- u- z-

The correct option is A 3log_ae #10; dydx= #10;3x^2x^3+y^^3+z^3 ( 1log_ea ) #10; x dydx= 3x^3x^3+y^^3+z^3log_ae #10; y dudx= 3y^3 ...

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nth Term of A.P

If u=logax3...

Question

If $u = {log}_{a} (x^{3} + y^{3} + z^{3})$ ,
then $x \frac{\partial u}{\partial x} + y \frac{\partial u}{\partial y} + z \frac{\partial u}{\partial z} = ?$

3 {log}_{a} e

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2 {log}_{a} e

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{log}_{a} e

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4 {log}_{a} e

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Solution

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Similar questions

u = (x^{3} + y^{3} + z^{3}) (x + y + z)

x \frac{\partial u}{\partial x} + y \frac{\partial u}{\partial y} + z \frac{\partial u}{\partial z} = ?

u = ∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & 1 x & y & z x^{2} & y^{2} & z^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣

x \frac{\partial u}{\partial x} + y \frac{\partial u}{\partial y} + z \frac{\partial u}{\partial z} =

u = \frac{y}{z} + \frac{z}{x}

x \frac{\partial u}{\partial x} + y \frac{\partial u}{\partial y} + z \frac{\partial u}{\partial z} = 0

u = \frac{1}{\sqrt{x^{2} + y^{2} + z^{2}}}

x \frac{\partial u}{\partial x} + y \frac{\partial u}{\partial y} + z \frac{\partial u}{\partial z} =

u = \sqrt{{sin}^{2} x + {sin}^{2} y + {sin}^{2} z}

\frac{\partial u}{\partial z}

(0, 0, \frac{π}{4}) = A

u = (x - y) (y - z) (z - x)

u_{x} + u_{y} + u_{z} = B

u = log (x^{3} + y^{3} + z^{3} - 3 x y z)

2 (\frac{\partial u}{\partial x} + \frac{\partial u}{\partial y} + \frac{\partial u}{\partial z})

(1, - 1, 3) = C

A, B, C

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