If U = {x: x is an english alphabet}(where U is an universal set) and AUB = {y: y is a vowel}, then $A^{c} ⋂ B^{c}$ is

Null set

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Set of consonants

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Set of vowels

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None of these

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Solution

The correct option is B Set of consonants

$A^{c} \cap B^{c} = (A \cup B)^{c} = \cup - (A \cup B)$
= Set of consonants
So, option B is correct

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If U = {x: x is an english alphabet}(where U is an universal set) and AUB = {y: y is a vowel}, then Ac⋂Bc is

The correct option is B Set of consonants Ac∩Bc=(A∪B)c=∪−(A∪B) = Set of consonants So, option B is correct

If U = {x: x is an english alphabet}(where U is an universal set) and AUB = {y: y is a vowel}, then $A^{c} ⋂ B^{c}$ is

The correct option is B Set of consonants

$A^{c} \cap B^{c} = (A \cup B)^{c} = \cup - (A \cup B)$
= Set of consonants
So, option B is correct