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Byju's Answer

Standard XII

Chemistry

1900's Physics and Wave

If uncertaini...

Question

If uncertainities in the measurement of position and momentum of an electron are equal, then uncertainity in the measurement of its velocity is approximately:

8.0 X10¹²m s^-1

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6.0 X 10¹²m s^-1

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4.0 X 10¹²m s^-1

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2.0 X 10¹²m s^-1

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Solution

The correct option is A
8.0 X10¹²m s^-1

$m^{2} Δ v^{2} = \frac{h}{4 π}$

$Δ r = \frac{1}{2 m} \sqrt{\frac{h}{π}} = \frac{1}{2 \times 9.1 \times 10^{- 31}} {(\frac{6.6 \times 10^{- 34}}{3.14})}^{\frac{1}{2}}$

= $8 \times 10^{12} m / s e c$

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If uncertainities in the measurement of position and momentum of an electron are equal, then uncertainity in the measurement of its velocity is approximately:

The correct option is A 8.0 X1012m s-1 m2 Δv2 = h4π Δr = 12m√hπ = 12 × 9.1 × 10−31(6.6 × 10−343.14)12 = 8 × 1012 m/sec

The correct option is A
8.0 X10¹²m s^-1

$m^{2} Δ v^{2} = \frac{h}{4 π}$

$Δ r = \frac{1}{2 m} \sqrt{\frac{h}{π}} = \frac{1}{2 \times 9.1 \times 10^{- 31}} {(\frac{6.6 \times 10^{- 34}}{3.14})}^{\frac{1}{2}}$

= $8 \times 10^{12} m / s e c$