If unit of length and force are increased $4$ times, the unit of energy

is increased by

4

times.

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is increased by

16

times.

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is increased by

8

times.

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remains unchanged.

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Solution

The correct option is B is increased by $16$ times.
As we know that, energy is the work done.
So, work done $=$ force $\times$ displacement
$∴$ unit, $u_{1} = F s = u (say)$
$\Rightarrow u_{2} = 4 F \times 4 s = 16 F s = 16 u$

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