If universal set - - a- b- c- d- e- f- g- h- A - b- c- d- e- f- B -a- b- c- g- h and C - c- d- e- f- g find B - C-

The correct option is C {c, d, e, f, g} Given : #160; ξ = {a, b, c, d, e, f, #160;g, h}, #160;A = {b, c, d, e, f}, #160;B ={a, b, c, g, h} ...

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Standard XII

Mathematics

Difference of Two Sets

If universal ...

Question

If universal set $ξ = {a, b, c, d, e, f, g, h}, A = {b, c, d, e, f}, B = {a, b, c, g, h}$ and $C = {c, d, e, f, g}$ find $(B - C)^{'}$

{d, e, f, g}

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{c, d, e, f, g}

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{c, d, f, g}

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{a, c, d, e, f, g}

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Solution

The correct option is C ${c, d, e, f, g}$
Given : $ξ = {a, b, c, d, e, f, g, h}, A = {b, c, d, e, f}, B = {a, b, c, g, h}$ and $C = {c, d, e, f, g}$
$B - C$ will have elements of $B$ which are not in $C$
So, $B - C = {a, b, h}$
And ${(B - C)}^{'} = ξ - (B - C) =$ { $c, d, e, f, g$ }

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Similar questions

Q. If universal set

ξ = {a, b, c, d, e, f, g, h}, A = {b, c, d, e, f}, B = {a, b, c, g, h}

and

C = {c, d, e, f, g}

, then find

B - A

Q. If

ξ

= {

a, b, c, d, e, f, g, h

A =

{

b, c, d, e, f

B =

{

a, b, c, g, h

} and

C =

{

c, d, e, f, g

} ,

then find

C

^{'}

- B

^{'}

Q. If a:b = c:d, and e:f = g:h, then (ae+bf):(ae-bf)=?

If universal set

ξ = {a, b, c, d, e, f, g, h}, A = {b, c, d, e, f}, B = {a, b, c, g, h}

and

C = {c, d, e, f, g}

find :

C - (B \cap A)

Thus find the number of elements in the above set.

Q. If

ξ

= {

a, b, c, d, e, f, g, h

A =

{

b, c, d, e, f

B =

{

a, b, c, g, h

} and

C =

{

c, d, e, f, g

then (B - C)

^{'}

= C

^{'}

- B

^{'}

is,

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If universal set ξ={a,b,c,d,e,f,g,h},A={b,c,d,e,f},B={a,b,c,g,h} and C={c,d,e,f,g} find (B−C)′

The correct option is C {c,d,e,f,g}Given : ξ={a,b,c,d,e,f,g,h},A={b,c,d,e,f},B={a,b,c,g,h} and C={c,d,e,f,g}B−C will have elements of B which are not in CSo, B−C={a,b,h} And (B−C)′=ξ−(B−C)= { c,d,e,f,g }

If universal set $ξ = {a, b, c, d, e, f, g, h}, A = {b, c, d, e, f}, B = {a, b, c, g, h}$ and $C = {c, d, e, f, g}$ find $(B - C)^{'}$

The correct option is C ${c, d, e, f, g}$
Given : $ξ = {a, b, c, d, e, f, g, h}, A = {b, c, d, e, f}, B = {a, b, c, g, h}$ and $C = {c, d, e, f, g}$
$B - C$ will have elements of $B$ which are not in $C$
So, $B - C = {a, b, h}$
And ${(B - C)}^{'} = ξ - (B - C) =$ { $c, d, e, f, g$ }