Question

If $V_0$ and $I_0$ are the peak current and voltage across the resistor in a series $L-C-R$ circuit, then the power dissipated in the circuit is

• A. $\frac{V_0{I}_0}{2}$
• B. $\frac{V_0{I}_0}{\sqrt{2}}$
• C. $V_0{I}_0\cos \phi$
• D. $\frac{V_0{I}_0}{2}\cos \phi$

Answer 1

The correct option is A $\frac{V_0{I}_0}{2}$

$P=P_R=\left(V_{rms}{)}_R\right(I_{rms}{)}_R$
$=\left(\frac{V_0}{\sqrt{2}}\right)\left(\frac{I_0}{\sqrt{2}}\right)=\frac{V_0{I}_0}{2}$

So, option $A$ is the correct answer.