Question

If V = 1 litre, 10 mole of $H_2$ and 10 mole of $N_2$ gas are mixed at temperature $26{}^{o}C$ then calculate pressure of the gas:

• A. $491atm$
• B. $300atm$
• C. $550atm$
• D. $600atm$

Answer 1

The correct option is A $491atm$

$PV=n_{T}RT$
Where, $n_T$ = Total moles of gases
$n_T=10+10=20mol$
$P=\frac{n_{T}RT}{V}=\frac{20\times 0.0821\times 299}{1}=491atm$