Question

If $v=(5-t)\text{m/s}$ and particle starts from origin then its position time graph is

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

$v=5-t\Rightarrow dx=(5-t)dt$
Integrating both sides w.r.t $t$, we get
$x=5t-\frac{t^2}{2}+c$
since particle starts from origin, $c=0$
So, the final equation of position is given by
$x=5t-\frac{t^2}{2}$