Question

If $V_B-V_A=4V$ in the given figure, Then resistance $X$ will be:

• A. $5\Omega$
• B. $10\Omega$
• C. $15\Omega$
• D. $20\Omega$

Answer 1

The correct option is D $20\Omega$

REF.Image.

Solution

$V_{B-A}=5-\left(V\right)$

$\Rightarrow V_B-V_A=5-V$

$\Rightarrow u=5-V\Rightarrow V=1V$

By ohm's low,

$V=\left(10\right)i$

$\Rightarrow 1/10A=i$

Also,

$V_{B-A}=2+V_x$

$\Rightarrow VX=4-2=2V$

By ohm's law

$V_x=xi$

$\Rightarrow 2=\times \left(\frac{1}{0}\right)\Rightarrow \times =20\Omega$

option - D is correct.