If V-D - 12 volt amp- V-E - 8 volt then V-A -56- voltV-B -68 -voltV-C -52 -voltV-B -48 -volt

The correct option is A V_A =56 volti = V_D V_E/R = 12 8/1 =4 A V_C =V_D +iR =12+4 × 2 =12 + 8 =20 V_B = V_C +iR =20+4 × 3 =20+12 = 32 V_A =V_B + iR =32+4 × ...

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Byju's Answer

Standard XII

Physics

Ohm's Law in Vector Form

If V_D = 12 v...

Question

If $V_{D} = 12$ volt & $V_{E} = 8$ volt then

V_{A} = 56 v o l t

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V_{B} = 68 v o l t

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V_{C} = 52 v o l t

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V_{B} = 48 v o l t

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Solution

The correct option is A $V_{A} = 56 v o l t$
$i = \frac{V_{D} - V_{E}}{R} = \frac{12 - 8}{1} = 4 A$
$V_{C} = V_{D} + i R = 12 + 4 \times 2 = 12 + 8 = 20$
$V_{B} = V_{C} + i R = 20 + 4 \times 3 = 20 + 12 = 32$
$V_{A} = V_{B} + i R = 32 + 4 \times 6 = 32 + 24 = 56$

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Similar questions

Q. In the uniform electric field shown in figure,

V_{D} - V_{B}

(in volts) is :

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V_{D} = 12

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Q. If

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and

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then

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If VD=12 volt & VE=8 volt then

The correct option is A VA=56 volti=VD−VER=12−81=4A VC=VD+iR=12+4×2=12+8=20 VB=VC+iR=20+4×3=20+12=32 VA=VB+iR=32+4×6=32+24=56

If $V_{D} = 12$ volt & $V_{E} = 8$ volt then

The correct option is A $V_{A} = 56 v o l t$
$i = \frac{V_{D} - V_{E}}{R} = \frac{12 - 8}{1} = 4 A$
$V_{C} = V_{D} + i R = 12 + 4 \times 2 = 12 + 8 = 20$
$V_{B} = V_{C} + i R = 20 + 4 \times 3 = 20 + 12 = 32$
$V_{A} = V_{B} + i R = 32 + 4 \times 6 = 32 + 24 = 56$