If Ve is the escape velocity of a body from a planet of mass M and radius R. Then, the velocity of satellite revolving at height h from the surface of planet will be
A
V=Ve√R(R+h)
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B
V=Ve√2R(R+h)
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C
V=Ve√(R+h)R
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D
V=Ve√R2(R+h)
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Solution
The correct option is CV=Ve√R2(R+h) The expression of escape velocity is Ve=√2GMR..................................(1) Let V be the velocity of satellite revolving at height h from the surface of planet. here, mV2(R+h)=GMm(R+h)2 or V=√GMR+h.......................(2) (2)/(1),V=Ve√R2(R+h)