Question

If 'V' is actual volume of 1 molecule of gas then,excluded volume(b) of 1 mole of gaseous molecule is?

• A. $4N_{A}V$
• B. $N_{A}V$
• C. ${V/N}_A$
• D. $V$

Answer 1

The correct option is A $4N_{A}V$

Solution:- (A) $4N_{A}V$

As we know that, exluded volume $\left(b\right)$ is given by-

$b=4\times \text{Volume of 1 mole of gas}$

Volume of $1$ mole of gas $=$ No. of molecules in $1$ mole $\times$ Volume of $1$ molecule

No. of molecules in $1$ mole of gas $=N_A$

Give that actual volume of $1$ molecue of gas is $V$.

$\therefore$ Volume of $1$ mole of gas $=N_A\times V$

$\therefore b=4\times N_A\times V$

Hence if $V$ is actual volume of $1$ molecule of gas then excluded volume $\left(b\right)$ of $1$ mole of gaseous molecule will be $4N_{A}V$.