Question

If V is the volume of a cuboid of dimensions x, y, z and A is its surface area, then $\frac{A}{V}$

(a) x²y²z²

(b) $\frac{1}{2}\left(\frac{1}{xy}+\frac{1}{yz}+\frac{1}{zx}\right)$

(c) $\left(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\right)$

(d) $\frac{1}{xyz}$

Answer 1

Dimensions of the cuboid are.

So, the surface area of the cuboid

Volume of the cuboid

Hence, the correct choice is (c).