If V is the volume of a cuboid of dimentions x, y, z and A is its surface area, then AV
2(1x+1y+1z)
A is surface area, V is volume and x, y and z are the dimensions
Then V = xyz
A=2[xy+yz+zx]
AV=2[xy+yz+zx]xyz
=2[xyxyz+yzxyz+zxxyz]
=2(1x+1y+1z)