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Question

If V is the volume of a cuboid of dimentions x, y, z and A is its surface area, then AV


A

x2y2z2

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B

12(1xy+1yz+1zx)

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C

2(1x+1y+1z)

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D

1xyz

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Solution

The correct option is C

2(1x+1y+1z)


A is surface area, V is volume and x, y and z are the dimensions

Then V = xyz

A=2[xy+yz+zx]

AV=2[xy+yz+zx]xyz

=2[xyxyz+yzxyz+zxxyz]

=2(1x+1y+1z)


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