Question

If $v$ is the volume of one molecule of a gas under given conditions, then van der Waals constant 'b' is : ($N_0$ = Avogadro's number)

• A. $4v$
• B. $\frac{4v}{N_0}$
• C. $\frac{N_0}{4v}$
• D. $4v{N}_0$

Answer 1

The correct option is D $4v{N}_0$

The van der Waals constant '$b$' is 4 times the volume of molecules in one mole (which has $N_0$ molecules) of a gas.
so, volume of $N_0$ molecules = $v{N}_0$
hence, $b=4v{N}_0$