If $v_{m}$ is the velocity of the sound in moist air and $V_{d}$ is the velocity of sound in dry air , under identical conditions of temperature and pressure . Then :

V_{m} > V_{d}

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V_{m} < V_{d}

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V_{m} = V_{d}

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V_{m} V_{d} = 1

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Solution

The correct option is C $V_{m} > V_{d}$
sound is nothing but vibration of air so in the presence of water in the air(moist air) the water droplet comes in contact with the vibration and amplify it because velocity of sound is higher in water than in air so amplified sound is created in moist air with higher velocity and obviously in the absence of water droplet or in dry air no amplification is possible and speed remains as it should be in air

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