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Question

If v mL of a gaseous hydrocarbon, after explosion with excess of oxygen, showed a contraction of 2.5 v mL and a further contraction of 2v mL with caustic potash. Find the number of carbon atoms in the hydrocarbon.

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Solution

Let the number of C atoms in the hydrocarbon be n.
CnH2n+2+3n+12O2nCO2+(n+1)H2O
Volume is directly proprtional to the number of moles of gas.
First contraction in volume is due to water.
Hence, n+1=2.5
n=1.52
Second contraction is due to carbon dioxide gas.
Hence, n=2

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