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Question

If value of x which satisfy equation: sin1[sin(2x2+41+x2)]<π3 is a<x<b.
Find the value of a+b.

A
2
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B
1
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C
0
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D
1
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Solution

The correct option is C 0
Given, sin1[sin(2x2+41+x2)]<π3 (i)
2x2+41+x2=2x2+2+21+x2=2+21+x2
Now 2+21+x2ϵ(2,4]
Therefor, Eq. (i) reduces to
π2x2+41+x2<π3
2x2+41+x2>3
2x2+4>3+3x2
x21<0
1<x<1

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