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Question

If |a|=1,|b|=2,|c|=3 and a+b+c=0, then the value of a.b+b.c+c.a equals

A
0
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B
7
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C
5
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D
143
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Solution

The correct option is B 7
|a|=1,b=2,|c|=3a+b+c=0a+b+c2=0(a+b+c)(a+b+c)=0a.a+a.b+a.c+b.a+b.b+b.c+c.a+c.b+c.c=0|a|2+b2+|c|2+2(a.b+b.c+c.a)=012+(2)2+32+2(a.b+b.c+c.a)=0a.b+b.c+c.a=7

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