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Question

If |a|=10,|b|=2 and a.b=12 , then what is the value of |a×b| ?

A
12
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B
16
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C
20
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D
24
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Solution

The correct option is B 16
If any two vectors a,b exist, then
value of dot product a.b is |a.b|=|a||b|cosA
A is the angle between them.
Given |a|=10 and |b|=2
and |a.b|=12
|a||b|cosA=12cosA=122×10=35sinA=1(35)2=1925=1625=45

Value of |a×b|=|a||b|sinA=10×2×45=16

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