If A- - 1-1-1 and C- - 0-1-1 are given vectors- then find a vector B- satisfying the equation A-B- - C- and A- B- -3

A⃗×B⃗=C⃗ A⃗× (A⃗×B⃗) =A⃗×C⃗ ⇒ (A⃗. B⃗) A⃗ (A⃗.A⃗)B⃗=A⃗×C⃗ ⇒ 3A⃗ 3B⃗=A⃗×C⃗ A⃗×C⃗ =î #160; amp; ĵ #160; amp; k̂ #160; 1 ...

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Condition for a Conic to Be a Pair of Straight Lines

If A⃗ = 1,1...

Question

If $\to A$ = (1,1,1) and $\to C$ = (0,1,1) are given vectors, then find a vector $\to B$ satisfying the equation $\to A \times \to B = \to C a n d \to A . \to B = 3$

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\to A = (1, 1, 1), \to C = (0, 1, - 1)

\to B

\to A \times \to B = \to C

\to A . \to B = 3

\to A = (1, 1, 1)

\to C = (0, 1, - 1)

\to B

\to A \times \to B = \to C

\to A . \to B = 3

-

\to a, \to b, \to c

\to b, \to c

(\to a, \to b) = α, (\to a, \to c) = β

\to a \times (\to b \times \to c) = \frac{\to b + \to c}{2}

c o s (α + β) =

\to A = \to b \times \to c, \to B = \to c \times \to a, \to C = \to a \times \to b

\to A \times (\to B \times \to C)

\to B \times (\to C \times \to A)

\to C \times (\to A \times \to B)

\to a, \to b, \to c

\to a + \to b + \to c = \to 0

(\to a, \to b) = \frac{π}{3}

∣ ∣ \to a \times \to b ∣ ∣ + ∣ ∣ \to b \times \to c ∣ ∣ + | \to c \times \to a | =

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