If -a-2 and -b-3 and a-b-0- then a- a- a- a-b- is equal to

The correct option is B 8b̂ |→a |=2 , |→b|=3 , →a→b=0⇒→a∥→b Now, →a× (→a×→b)=(→a·→b)→a (→a·→a)→b =0 4→b= 4→b ∴ (→a×(→a× (→a×→ ...

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Lines Perpendicular to the Same Line Are Parallel

If |a⃗|=2 a...

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If $| \to a | = 2$ and $| \to b | = 3$ and $\to a \to b = 0$ , then $(\to a \times (\to a \times (\to a \times (\to a \times \to b))))$ is equal to

48^b

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8^b

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48^a

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- 48^a

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\to A B = \to a, \to B C = \to b

\to A B = \to a, + \to b

\to B D = \to b, - \to a

| \to a | = 3, ∣ ∣ \to b ∣ ∣ = 4, | \to c | = 5, \to a ⊥ (\to b + \to c), \to b ⊥ (\to c + \to a)

\to c ⊥ (\to a + \to b)

\sqrt{2} ∣ ∣ \to a + \to b + \to c ∣ ∣

\to r \times \to a = \to b \times \to a; \to r \times \to b = \to a \times \to b; \to a \neq 0, \to b \neq 0, \to a \neq λ \to b; \to a

\to b

\to r =

| \to a | = 7, | \to b | = 11

| \to a + \to b | = 10 \sqrt{3}

| \to a - \to b |

(\to a + \to b) \cdot (\to a + \to b) = {| \to a |}^{2} + {∣ ∣ \to b ∣ ∣}^{2}

\to a \to b

\to a \neq \to 0, \to b \neq \to 0

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