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Question

If A=2^i+7^j+3^k and B=3^i+2^j+5^k, find the component of A along B.

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Solution

The component of A along B is |A|cosθ^B

=B(A.B)|B|2=[3^i+2^j+5^k](2^i+7^j+3^k).(3^i+2^j+5^k)32+22+52

=(3^i+2^j+5^k)(6+14+15)38

=(3538)(3^i+2^j+5^k)



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