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Question

If a=2^i+^j+3^k,b=p^i+^j+q^k and b×a=0, then

A
(p,q)=(2,3)
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B
(p,q)=(2,3)
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C
(p,q)=(1,2)
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D
(p,q)=(1,2)
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Solution

The correct option is A (p,q)=(2,3)
b×a=∣ ∣ ∣^i^j^k213p1q∣ ∣ ∣=(q3)^i+(3p2q)^j+(2p)^k
b×a=0
So q=3 P=2

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