If A- - 2- - - - k- and B- - - - - - k- are two vectors- then the unit vector is

The correct options are A Perpendicular to A⃗ is ĵ + k̂√(2) C Perpendicular to B⃗ is (ĵ + k̂√(2)) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Theorems for Differentiability

If A⃗ = 2î ...

Question

If $\to A = 2^i +^j +^k$ and $\to B =^i +^j +^k$ are two vectors, then the unit vector is

Perpendicular to

\to A

\frac{-^j +^k}{\sqrt{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Parallel to

\to A

\frac{2^i +^j +^k}{\sqrt{6}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Perpendicular to

\to B

(\frac{^j +^k}{\sqrt{2}})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Parallel to

\to A

\frac{^i +^j +^k}{\sqrt{3}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\to a =^i +^j +^k

\to b =^i -^j +^k

\to c =^i +^j -^k

\to a =^i -^j -^k

(\to a \times \to b) \times (\to c \times \to d)

\to a = 2^i + 4^j - 5^k, \to b =^i +^j +^k, \to c =^j + 2^k

\to a + \to b + \to c

\to a =^i -^j -^k

\to b = 2^i +^j -^k

\to a = 3^i +^j +^k, \to b =^i -^j + 2^k a n d \to c = 2^i -^j -^k

\to d

¯ d

\to c

\to d

\to a = 10, \to b = 1

A

^i +^j +^k

2^i +^j + 3^k

2^i -^j -^k

R

\to a, \to b

\to a \times \to b

Join BYJU'S Learning Program