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Question

If |a|=2,|b|=7 and a×b=3^i+2^j+6^k then the angle between a and b is

A
π3
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B
π6
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C
π2
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D
π4
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Solution

The correct option is A π6
|a|=2,|b|=7 and a×b=3^i+2^j+6^k
|a×b|=|a||b|sinθ|^n|
9+4+36=2.7.sinθ.1
49=2.7×sinθ
7=7.2sinθ
sinθ=12
θ=π6

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