If a-2i-j-k- - b-i-2j-3k- - c-3i-j-5k- are coplanar then - is a root of the equation

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Condition for Coplanarity of Four Points

If a⃗=2i⃗-j...

Question

If $\to a = 2 \to i - \to j + \to k$ , $\to b = \to i + 2 \to j - 3 \to k$ , $\to c = 3 \to i + μ \to j + 5 \to k$ are coplanar then $μ$ is a root of the equation

x^{2} + 3 x = 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x^{2} + 2 x = 6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} + 3 x = 6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x + 5 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\to a = \to i - 2 \to j - 3 \to k, \to b = 2 \to i + \to j - \to k, \to c = \to i + 3 \to j - 2 \to k

(\to a \times \to b) \times \to c

\to r = 3 \to i + 2 \to j - 5 \to k

\to a = 2 \to i - \to j + \to k

\to b = \to i + 3 \to j - 2 \to k

\to c = - 2 \to i + \to j - 3 \to k

\to r = λ \to a + μ \to b + ν \to c

\to r = \to i + 2 \to j + 3 \to k + λ (\to i - \to j + \to k) a n d \to r = 2 \to i - \to j - \to k + μ (\to - i + \to j - \to k) i s

\to a = \to i + \to j + \to k, \to a = 2 \to i + \to k, \to c = 2 \to i + \to j + \to k; \to d = \to i + \to j + 2 \to k

(\to a \times \to b) \times (\to c \times \to d) = [\to a \to b \to d] \to c - [\to a \to b \to c] \to d

\to a = 3 \to i + 2 \to j + 6 \to k

\to b = 2 \to i + \to j + \to k

\to c = \to i - \to j + \to k

Join BYJU'S Learning Program