If -a-4- -b-2 and the angle between a- and b- is -6 then a-b-2 is

The correct option is D 16 We have (a×b)^2+(a b)^2=|a|^2|b|^2 (a×b)^2=64 (4×2cosπ6)^2 =64 16×3 =16 ...

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Vector Component

If |a⃗|=4, ...

Question

If $| \to a | = 4, | \to b | = 2$ and the angle between $\to a$ and $\to b$ is $\frac{π}{6}$ then $(\to a \times \to b)^{2}$ is

48

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8

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16

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32

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Similar questions

| \to a | = 4 | \to b | = 2

\to a

\to b

\frac{π}{6}

(\to a \times \to b)^{2}

\to a, \to b, \to c

\to a, \to b

\to b, \to c

\to c, \to a

\frac{π}{6}, \frac{π}{3}

\frac{π}{4}

| \to a + \to b + \to c |

\to A

\to B

\to A \times \to B = \to B \times \to A

\to A

\to B

Let the vectors and be such that and, then is a unit vector, if the angle between and is

(A) (B) (C) (D)

\to a, \to b, \to c

\to c

\to a

\to b

\to a

\to b

\frac{π}{6}

[\to a \to b \to c]^{2} = \frac{1}{4} | \to a |^{2} | \to b |^{2}

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