If -a-5- -a-b-8 and -a-b-10- then -b- is equal to -

The correct option is C √(57) [ | a⃗ #160; | =5,| a⃗ b⃗ #160; | =8,| a⃗ +b⃗ #160; | =10; | a⃗ b⃗ #160; ...

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Addition of Vectors

If |a⃗|=5, ...

Question

If $| \to a | = 5, | \to a - \to b | = 8$ and $| \to a + \to b | = 10$ , then $| \to b |$ is equal to :

1

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\sqrt{57}

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Solution

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Similar questions

| \to a | = 5

∣ ∣ \to a - \to b ∣ ∣ = 8

∣ ∣ \to a + \to b ∣ ∣ = 10

∣ ∣ \to b ∣ ∣

\to a, \to b

\to c

\to b + \to c, \to c + \to a

\to a + \to b

| \to a + \to b | = 6, | \to b + \to c | = 8

| \to c + \to a | = 10

| \to a + \to b + \to c |

| \to a | = 3, ∣ ∣ \to b ∣ ∣ = 4, | \to c | = 5, \to a ⊥ (\to b + \to c), \to b ⊥ (\to c + \to a)

\to c ⊥ (\to a + \to b)

\sqrt{2} ∣ ∣ \to a + \to b + \to c ∣ ∣

| \to a | = | \to b | = | \to a + \to b | = 1, t h e n | \to a - \to b |

| \to a | = 7, | \to b | = 11

| \to a + \to b | = 10 \sqrt{3}

| \to a - \to b |

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