If a- and b- are non-zero non-collinear vectors- then - a- b- - - - a- b- - - - a- b- k- k- is equal to

The correct option is B a⃗×b⃗ Let a⃗= a_1î + a_2 ĵ+ a_3 k̂ b⃗ = b_1î+ b_2 ĵ + b_3 k̂ [a⃗ b⃗ c⃗]. î+ [a⃗ b⃗] ĵ + [a⃗ b⃗ k̂] k̂ = ( ( ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Addition of Vectors

If a⃗ and ...

Question

If $\to a$ and $\to b$ are non-zero non-collinear vectors, then $[\to a \to b^i]^i + [\to a \to b^j]^j + [\to a \to b^k]^k$ is equal to

\to a + \to b

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\to a \times \to b

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\to a - \to b

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\to b \times \to a

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\to a, \to b, \to c

\to a \times \to b = \to b \times \to c = \to c \times \to a

\to a + \to b + \to c =

\to a

\to b

\to a + \to b

\to a - \to b

\to a =^i +^j, \to b =^i +^k

{{(\to a \times \to b) \times \to a} \times \to a} \times \to b =

\to a, \to b, \to c

{\to a \times (\to b + \to c)} \times {\to b \times (\to c - \to a)}

\to a, \to b, \to c

(\to a \times \to b) \times (\to a \times \to c) + (\to b \times \to c) \times (\to b \times \to a) + (\to c \times \to a) \times (\to c \times \to b)

Join BYJU'S Learning Program