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Question

If a and b are non-zero non-collinear vectors, then [ab^i]^i+[ab^j]^j+[ab^k]^k is equal to

A
a+b
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B
a×b
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C
ab
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D
b×a
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Solution

The correct option is B a×b
Let a=a1^i+a2^j+a3^k
b=b1^i+b2^j+b3^k
[abc].^i+[ab]^j+[ab^k]^k
=((a×b)^i)^i+((a×b)^j)^j+((a×b).^k)^k
=a×b

1080076_793336_ans_4acb916a451d45199890598f7774e473.jpg

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