If →a and →b are two vectors such that →a.→b=0 and →a×→b=→0, then
A
→a||→b
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B
→a⊥→b
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C
eitherparallelorperpedicular
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D
Noneoftheabove
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Solution
The correct option is DNoneoftheabove We have, →a.→b=0 and →a×→b=→0 ⇒|→a||→b|cosθ=0 and |→a||→b|sinθ=0 ⇒|→a|=0 or |→b|=0orcosθ=0 and |→a|=0|→b|=0 or sinθ=0