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Byju's Answer
Standard XII
Mathematics
Applications of Dot Product
If a⃗ and ...
Question
If
→
a
and
→
b
are unit vectors and
|
→
a
+
→
b
|
=
1
then
|
→
a
−
→
b
|
is equal to.
A
√
2
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B
1
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C
√
5
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D
√
3
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Solution
The correct option is
D
√
3
Given
→
a
,
→
b
are unit vectors.
|
a
+
b
|
=
√
|
→
a
|
2
+
|
→
b
|
2
+
2
|
a
|
|
b
|
cos
θ
=
1
⇒
cos
θ
=
1
−
1
−
1
2
=
−
1
2
|
→
a
−
→
b
|
=
√
|
→
a
|
2
+
|
→
b
|
2
−
2
|
a
|
|
b
|
c
o
s
θ
=
√
(
|
→
a
+
→
b
|
)
2
−
4
|
a
|
|
b
|
c
o
s
θ
=
√
1
2
−
4
|
a
|
|
b
|
cos
θ
=
√
1
2
−
4
(
−
1
2
)
=
√
3
Hence, option D is correct.
Suggest Corrections
0
Similar questions
Q.
I : If
|
→
a
+
→
b
|
=
|
→
a
−
→
b
|
, then
(
→
a
,
→
b
)
=
π
2
.
II : If
→
a
,
→
b
,
→
a
+
→
b
are unit vectors, then
(
→
a
,
→
b
)
=
2
π
3
.
Q.
If
→
a
,
→
b
,
→
c
are unit vectors such that
→
a
+
→
b
+
→
c
=
→
0
and
(
→
a
,
→
b
)
=
π
3
, then
∣
∣
→
a
×
→
b
∣
∣
+
∣
∣
→
b
×
→
c
∣
∣
+
|
→
c
×
→
a
|
=
Q.
Let
→
a
and
→
b
are two vectors, such that
|
→
a
|
=
3
and
|
→
b
|
=
2
. If
→
a
−
→
b
is unit vector, then the acute angle between
→
a
and
→
b
is ______
Q.
Let
→
a
and
→
b
be two unit vectors. the maximum value of
∣
∣
→
a
+
→
b
∣
∣
2
−
∣
∣
→
a
−
→
b
∣
∣
2
∣
∣
→
a
+
→
b
∣
∣
2
+
∣
∣
→
a
−
→
b
∣
∣
2
is equal to
Q.
If
→
a
,
→
b
,
→
c
are unit vectors such that
→
a
+
→
b
+
→
c
=
→
0
and
(
→
a
,
→
b
)
=
π
3
then
|
→
a
×
→
b
|
+
|
→
b
×
→
c
|
+
|
→
c
×
→
a
|
=
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