If a- and b- are unit vectors such that a-b-2a-3b- 3a-2b-0

The correct option is A 0 (a⃗+b⃗).(2a⃗+3b⃗)× (3a⃗ 2b⃗) =(a⃗+b⃗)[2a⃗× 3a⃗ 2a⃗× 2b⃗+3b⃗× 3a⃗ 3b⃗× 2b⃗] =(a⃗+b⃗) [0+4b⃗×a⃗+9b⃗×a⃗ 0] =(a⃗+ ...

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Reversing the 2 Digit Numbers and Adding Them

If a⃗ and ...

Question

If $\to a$ and $\to b$ are unit vectors such that $(\to a + \to b) . (2 \to a + 3 \to b) \times (3 \to a - 2 \to b) = 0$

0

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\frac{π}{2}

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π

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Indeterminate

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Solution

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Similar questions

\to a

\to b

| \to a | = 3

| \to b | = 6

| \to a + \to b | = 7

(3 \to a - 2 \to b) . (2 \to a + 5 \to b - 4 \to a \times \to b)

\to a

\to b

| \to a + \to b | = \sqrt{3} .

\to c = \to a + 2 \to b + 3 (\to a \times \to b),

2 | \to c |

\to a, \to b, \to c

2 \to a + \to b, \to a + 2 \to b + \to c, 4 \to a - 2 \to b - \to c

3 \to a + 4 \to b - 5 \to c

\to a

\to b

| \to a + \to b | = \sqrt{3}

(2 \to a - 5 \to b) . (3 \to a + \to b) =

\to a

\to b

| \to a + \to b | = \sqrt{3}

(2 \to a + 5 \to b) \cdot (3 \to a + \to b + \to a \times \to b)

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