MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Isometric Sketch

If a⃗=î+2 ĵ+2...

Question

If $\to a =^i + 2^j + 2^k$ and $\to b = 3^i + 6^j + 2^k$ , then the vector in the direction of $\to a$ and having magnitude as $| \to b |$ , is

A

7 (^i + 2^j + 2^k)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

\frac{7}{9} (^i + 2^j + 2^k)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

\frac{7}{3} (^i + 2^j + 2^k)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

N o n e o f t h e s e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{7}{3} (^i + 2^j + 2^k)$
The required vectors
$= | \to b |^a = \frac{| \to b |}{| \to a |} \to a = \frac{7}{3} (^i + 2^j + 2^k)$

Suggest Corrections

thumbs-up

1

Similar questions

The vector in the direction of the vector $^i - 2^j + 2^k$ that has magnitude 9 is

(a) $^i - 2^j + 2^k$

(b) $\frac{^i - 2^j + 2^k}{3}$

(c) $3 (^i - 2^j + 2^k)$

(d) $9 (^i - 2^j + 2^k)$

\to a =^i + 2^j + 2^k

\to b = 3^i + 6^j + 2^k

, then the vector in the direction of

\to a

and having magnitude as

| \to b |

Q. If direction cosines of a vector of magnitude

3

\frac{2}{3}, \frac{- 1}{3}, \frac{2}{3}

a > 0

, then vector is

\to a = 3^i + 2^j + 2^k, b =^i + 2^j - 2^k

. Then a unit vector perpendicular to both

\to a - \to b

\to a + \to b

\to a = 3^i + 2^j + 2^k

\to b =^i + 2^j - 2^k

. Then a vector of magnitude

12

, which is perpendicular to both

\to a + \to b

\to a - \to b

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Drawing 3-Dimensional Shapes

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Isometric Sketch

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon