If a-2- -k- b-k- then the point of intersection of lines r-a-b-a- and r-b-a-b- is

The correct option is C î ĵ+2k̂ Line 1, #160; r× #160;a=b× #160;a ⇒ (r b)× #160;a=0 ⇒ #160;r b=λ #160;a ⇒ #160;r=b + λ ...

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Angle between a Plane and a Line

If a⃗=î-2ĵ ...

Question

If $\to a =^i - 2^j +^k, \to b =^j +^k$ , then the point of intersection of lines $\to r \times \to a = \to b \times \to a$ and $\to r \times \to b = \to a \times \to b$ is

^i +^j +^k

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^i - 3^j

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^i -^j + 2^k

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- 3^i -^j +^k

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Solution

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Similar questions

\to a = 3^i + 2^j + 2^k, \to b = -^i + 3^j -^k, \to c =^i +^j +^k

\to a \times (\to b \times \to c)

(\to a \times \to b) \times \to c

\to a =^i +^j

\to b = 2^i -^k

\to r \times \to a = \to b \times \to a

\to r \times \to b = \to a \times \to b

\to a =^i +^j +^k, \to b =^i +^j -^k

\to c =^i -^j +^k

\to d =^i -^j -^k

(\to a \times \to b) \times (\to c \times \to d) =

\to a =^i +^j +^k

\to b =^i -^j +^k

\to c =^i +^j -^k

\to a =^i -^j -^k

(\to a \times \to b) \times (\to c \times \to d)

\to a = 2^i +^j + 3^k

\to b = 3^i + 2^j +^k

\to c =^i -^j - 4^k

\to d =^i + 2^j -^k

(\to a \times \to b) \times (\to c \times \to d) =

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