If →A=^iAcosθ+^jAsinθ, then another vector →B which is orthogonal to →A can be expressed as:
A
^iBcosθ−^jBsinθ
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B
^iBsinθ−^jBcosθ
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C
^iBcosθ+^jBsinθ
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D
^iBsinθ+^jBcosθ
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Solution
The correct option is B^iBsinθ−^jBcosθ Two vectors are said to be orthogonal when their dot product is zero. →A=^iAcosθ+^jAsinθ [use option to reduce time] From option (b) ^iBsinθ−^jBcosθ →A.(→B)=ABsinθcosθ−ABsinθcosθ=0