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Question

If a=^i+^j+^k and b=2^j3^k+^k, then find:
(i)Component of b along a
(ii)Component of b perpendicular to along a

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Solution

Given,

a=^i+^j+^k,b=2^j3^k+^k

^a=13(^i+^j+^k)unitvector

Component of b along a is b.^a=(2^j3^k+^k).[13(^i+^j+^k)]=13(23+1)=0.

Component of b normal to a is b×^a

ijk231111 = 4^i1^j+5^k

(i) Component of b along a is zero.

(ii) Component of b normal to a is 4^i1^j+5^k .


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