If →a=^i+^j+^k,→b=2^i−^j+^k and →c=^i+x^j+y^k, are linearly dependent and |→c|=√3 then (x,y) is
A
(-1, -1)
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B
(2,3)
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C
(3,1)
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Solution
The correct option is A (-1, -1) Given that the three vectors are linearly dependent so →c=l→a+m→b ⇒l+2m=1(Comparing the ^i components) l−m=x (Comparing the ^j components) ⇒x−3y=2 I +m =y (Comparing the ^k components) Also, x2+y2+1=3 10y2+12y+2=0 ⇒y=−1,−15 x=−1,75