If →a=^i+^j+^k, →b=^i−^j+^k, →c=^i+^j−^k and →a=^i−^j−^k, then (→a×→b)×(→c×→d) is a vector orthogonal to both
A
^i and^j
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B
^j and ^k
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C
^k and ^i
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D
^i and ^j and ^j and ^k
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Solution
The correct option is B^k and ^i ¯¯¯aׯ¯b=2i−2k ...(i) ¯¯cׯ¯¯d=−2i−2k ...(ii) Hence (2i−2k)×(−2i−2k) =4j+4j =8j Hence the resultant vector is orthogonal to k and i.