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Question

If a=^i+^j+^k, b=^i+^j,c=^i and (a×b)×c=λa+μb, then λ+μ=

A
1
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C
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2
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Solution

The correct option is A 0
a×b=^i+^j
c=^i
Hence
(a×b)×c
=(^i+^j)×(^i)
=^k
λa+μb
=(λ+μ)^i+(λ+μ)^j+λ^k
Comparing coefficients, we get
λ+μ=0 and
λ=1
Hence μ=1

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