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Question

If a=i+jk,b=ij+k,c is a vector perpendicular to a and coplanar with a and b then c=

A
16(2i+j+k)
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B
±16(2ij+k)
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C
16(2i+jk)
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D
16(2ijk)
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Solution

The correct option is B ±16(2ij+k)
Let c=x^i+y^j+z^k
ac=a.c=0
x+yz=0
Also a,b,c are co planar
∣ ∣xyz111111∣ ∣=0
x(0)y(2)+z(2)=0
2y+2z=0y+z=0y=z
x+y+y=0
x+2y=0x=2y
^c=±16(2ij+k)

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