If →a×(→b×→c)=(→a×→b)×→c for non-coplanar vectors →a, →b, →c then
A
→a parallel to →b
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B
→b parallel to →c
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C
→c parallel to →a
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D
→a+→b+→c=→0
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Solution
The correct option is C→c parallel to →a Now, according to the vector cross product rule, →a×(→b×→c)=(→a.→c)→b−(→a.→b)→c................(1) and (→a×→b)×→c=(→a.→c)→b−(→b.→c)→a ..............(2) Equating both the equations we get, (→a.→b)→c=(→b.→c)→a ∴→c is parallel to →a.