If -a-b- - 5 and -a-b- - 3 then -a-2 -b-2 is equal to

The correct option is D 34 We know that, #160; |a⃗× #160;b⃗|^2 = |a⃗|^2 |b⃗|^2 (a⃗ . #160;b⃗)^2 ⇒ 25 = |a⃗|^2 |b⃗|^2 9 ∴ ...

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Byju's Answer

Standard XII

Mathematics

Relation between AM,GM,HM for 2 Numbers

If |a⃗×b⃗| ...

Question

If $| \to a \times \to b | = 5$ and $| \to a \cdot \to b | = 3$ then $| \to a |^{2} | \to b |^{2}$ is equal to

16

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34

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Solution

The correct option is D $34$
We know that,
$| \to a \times \to b |^{2} = | \to a |^{2} | \to b |^{2} - (\to a . \to b)^{2}$
$\Rightarrow 25 = | \to a |^{2} | \to b |^{2} - 9$
$∴ | \to a |^{2} | \to b |^{2} = 34$

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If |→a×→b|=5 and |→a⋅→b|=3 then |→a|2|→b|2 is equal to

The correct option is D 34We know that, |→a×→b|2=|→a|2|→b|2−(→a.→b)2⇒ 25=|→a|2|→b|2−9∴|→a|2|→b|2=34

If $| \to a \times \to b | = 5$ and $| \to a \cdot \to b | = 3$ then $| \to a |^{2} | \to b |^{2}$ is equal to

The correct option is D $34$
We know that,
$| \to a \times \to b |^{2} = | \to a |^{2} | \to b |^{2} - (\to a . \to b)^{2}$
$\Rightarrow 25 = | \to a |^{2} | \to b |^{2} - 9$
$∴ | \to a |^{2} | \to b |^{2} = 34$