If a-b- -b-c- -c-a- then a- -b- -c- -

The correct option is C 0 ×b⃗=b⃗×c⃗=c⃗×a⃗⇒ ...... (1) ⇒ b⃗×a⃗= c⃗×b⃗= a⃗×c⃗ ........... (2) (a⃗+b⃗+c⃗)^2=(a⃗+b⃗+c⃗)× (a⃗+b⃗+c⃗) ...

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If a⃗×b⃗ =b...

Question

If $\to a \times \to b = \to b \times \to c = \to c \times \to a$ then $\to a + \to b + \to c =$

a b c

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Similar questions

| \to a | = 1, ∣ ∣ \to b ∣ ∣ = \sqrt{2}

| \to c | = \sqrt{3}

\to a ⊥ (\to b + \to c)

\to b ⊥ (\to c + \to a)

\to c ⊥ (\to a + \to b)

∣ ∣ \to a + \to b + \to c ∣ ∣

\to A = \to b \times \to c, \to B = \to c \times \to a, \to C = \to a \times \to b

\to A \times (\to B \times \to C)

\to B \times (\to C \times \to A)

\to C \times (\to A \times \to B)

| \to a | = 3, ∣ ∣ \to b ∣ ∣ = 4, | \to c | = 5, \to a ⊥ (\to b + \to c), \to b ⊥ (\to c + \to a)

\to c ⊥ (\to a + \to b)

\sqrt{2} ∣ ∣ \to a + \to b + \to c ∣ ∣

(\to b \times \to c) \times (\to c \times \to a) = 3 \to c

[\to b \times \to c

\to c \times \to a

\to a \times \to b] =

\to a =^i +^j +^k

\to b = - 3^i +^k

\to c =^i + 2^j + 3^k

A)

[\to a \times \to b

\to b \times \to c

\to c \times \to a]

B)

[\to a + \to b

\to b + \to c

\to c + \to a]

C)

[\to a

\to b

\to c]

[\to a

\to b

\to c]^{- 1}

D)

[\to a - \to b

\to b - \to c

\to c - \to a]

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