If a-b-c-d- and a-c-b-d- then a-d-b-c- are

The correct option is A ParallelGiven that #160; a⃗×b⃗ = c⃗×d⃗— 1 a⃗×c⃗ = b⃗×d⃗— 2 Subtract #160; (1) (2) #160; a⃗× (b⃗ c⃗)= (c⃗ d⃗)×d ...

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Square

If a⃗×b⃗=c⃗...

Question

If $\to a \times \to b = \to c \times \to d$ and $\to a \times \to c = \to b \times \to d$ , then $\to a - \to d, \to b - \to c$ are

Parallel

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Perpendicular

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Are inclined at an angle of

45^{0}

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Are inclined at an angle of

60^{0}

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Solution

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Similar questions

\to a \times \to b = \to c \times \to d

\to a \times \to c = \to b \times \to d

\to a - \to d

\to b - \to c

\to a, \to b, \to c, \to d

(\to a \times \to b) \times (\to c \times \to d) + (\to a \times \to c) \times (\to d \times \to b) + (\to a \times \to d) \times (\to b \times \to c)

\to b, \to c, \to d

(\to a \times \to b) \times (\to c \times \to d) + (\to a \times \to c) \times (\to d \times \to b) + (\to a \times \to d) \times (\to b \times \to c)

\to b, \to c, \to d

(\to a \times \to b) \times (\to c \times \to d) + (\to a \times \to c) \times (\to d \times \to b) + (\to a \times \to d) \times (\to b \times \to c)

\to a, \to b, \to c, \to d

{(\to a \times \to b) \times (\to c \times \to d)} \times (\to a - \to b) =

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